1. 次の2次方程式を解け
12x2-x-1=0
32x2-48x+18=0
4x2+4x-13=0
13x2+53x+1912=0
16x2+23x=80
(2x+1)(x-3)3=x(4x-3)4-10
(3x-1)22=(2x+1)(3x-7)3+3
(2x-7)2+3(7-2x)-180=0
12x2-x-1=0
x=1±1+4×12×124
=1±4924
=1±724
=824,-624
=13,-14
32x2-48x+18=0
16x2-24+9=0
(4x-3)2=0
x=34
4x2+4x-13=0
x=-4±16+4×4×138
=-4±2248
=-4±4148
=-1±142
13x2+53x+1912=0
4x2+20x+19=0
x=-20±400-4×4×198
=-20±968
=-20±468
=-5±62
16x2+23x=80
x2+4x-480=0
(x+24)(x-20)=0
x=-24,20
(2x+1)(x-3)3=x(4x-3)4-10
4(2x+1)(x-3)=3x(4x-3)-120
8x2-20x-12=12x2-9x-120
4x2+11x-108=0
x=-11±121+4×4×1088
=-11±438
=4,-274
(3x-1)22=(2x+1)(3x-7)3+3
3(3x-1)2 = 2(2x+1)(3x-7)+18
3(9x2-6x+1) = 2(6x2-11x-7)+18
27x2-18x+3 = 12x2-22x-14+18
(27-12)x2 + (-18+22)x +3+14-18 = 0
15x2 + 4x -1 = 0
x= -4±16-4×15×(-1)30
x= -4±7630
x= -4±21930
x= -2±1915
(2x-7)2+3(7-2x)-180=0
(2x-7)2-3(2x-7)-180=0
A2-3A-180=0
(A-15)(A+12)=0
(2x-7-15)(2x-7+12)=0
(2x-22)(2x+5)=0
x=11,-52
