展開L3-1-1(6問)
次の式を展開せよ。
(a+b)(a+b+1)
解答○ ×(x+1)(x+y+2)
解答○ ×(x+2y+3)(x-1)
解答○ ×(a+b-1)(a-2)
解答○ ×(2x-3y+1)(x+y)
解答○ ×(x-y+4)(x+y)
解答○ ×問題と解答
(a+b)(a+b+1)a2+2ab+b2+a+b (x+1)(x+y+2)x2+xy+3x+y+2 (x+2y+3)(x-1)x2+2xy+2x-2y-3 (a+b-1)(a-2)a2+ab-3a-2b+2 (2x-3y+1)(x+y)2x2-3y2-xy+x+y (x-y+4)(x+y)x2-y2+4x+4y
