展開L3-1-3(6問)
次の式を展開せよ。
(a+b+1)(a+b-1)
解答○ ×(a-b+1)(a+b+1)
解答○ ×(x+y+z)2
解答○ ×(2x+y+3)(2x-y-3)
解答○ ×(x+2y-1)2
解答○ ×(a+2b+3c)(a-b+2c)
解答○ ×問題と解答
(a+b+1)(a+b-1)a2+2ab+b2-1 (a-b+1)(a+b+1)a2+2a-b2+1 (x+y+z)2x2+y2+z2+2xy+2yz+2xz (2x+y+3)(2x-y-3)4x2-y2-6y-9 (x+2y-1)2x2+4xy+4y2-2x-4y+1 (a+2b+3c)(a-b+2c)a2-2b2+6c2+ab+bc+6ac
