展開L2-2-8(8問)
次の計算をせよ。
(2x+1)(3x-1)+(4x+1)(x-3)
解答○ ×(3x+2)(4x-1)+(2x-1)(2x-3)
解答○ ×(4x-3)2-(3x-1)(5x+4)
解答○ ×(3x+2)(2x+7)-(2x+5)2
解答○ ×(4x+5)(4x-5)+(5x-6)(3x-4)
解答○ ×(2x+3)(4x-1)-(x+2)(5x+3)
解答○ ×(5x+1)2+(-4x+3)(6x+5)
解答○ ×(3x+7)2-(2x+9)2
解答○ ×問題と解答
(2x+1)(3x-1)+(4x+1)(x-3)10x2-10x-4 (3x+2)(4x-1)+(2x-1)(2x-3)16x2-3x+1 (4x-3)2-(3x-1)(5x+4)x2-31x+13 (3x+2)(2x+7)-(2x+5)22x2+5x-11 (4x+5)(4x-5)+(5x-6)(3x-4)31x2-38x-1 (2x+3)(4x-1)-(x+2)(5x+3)3x2-3x-9 (5x+1)2+(-4x+3)(6x+5)x2+8x+16 (3x+7)2-(2x+9)25x2+6x-32
