展開(分配法則)-4(6問)
次の式を展開せよ。
(4x2y+9xy2)÷6xy
解答○ ×(3a2b3-6a2b)÷(-9a2b)
解答○ ×(6x3y2+4x2y+8xy2)÷12xy
解答○ ×(2a2b3-3a2b2-6ab2)÷6ab2
解答○ ×(4x3y2-9x2y3+6x2y2)÷(-12xy2)
解答○ ×(x4y2-12x3y2-9x3y)÷(-6x2y)
解答○ ×問題と解答
(4x2y+9xy2)÷6xy23x+32y (3a2b3-6a2b)÷(-9a2b)-13b2+23 (6x3y2+4x2y+8xy2)÷12xy12x2y+13x+23y (2a2b3-3a2b2-6ab2)÷6ab213ab-12a-1 (4x3y2-9x2y3+6x2y2)÷(-12xy2)-13x2+34xy-12x (x4y2-12x3y2-9x3y)÷(-6x2y)-16x2y+2xy+32x
